Optimal. Leaf size=134 \[ \frac {a (2 c-d) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{(c+d) \left (c^2-d^2\right )^{3/2} f}-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {a (c-2 d) \cos (e+f x)}{2 (c-d) (c+d)^2 f (c+d \sin (e+f x))} \]
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Rubi [A]
time = 0.14, antiderivative size = 134, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {2833, 12, 2739,
632, 210} \begin {gather*} \frac {a (2 c-d) \text {ArcTan}\left (\frac {c \tan \left (\frac {1}{2} (e+f x)\right )+d}{\sqrt {c^2-d^2}}\right )}{f (c+d) \left (c^2-d^2\right )^{3/2}}-\frac {a (c-2 d) \cos (e+f x)}{2 f (c-d) (c+d)^2 (c+d \sin (e+f x))}-\frac {a \cos (e+f x)}{2 f (c+d) (c+d \sin (e+f x))^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 210
Rule 632
Rule 2739
Rule 2833
Rubi steps
\begin {align*} \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^3} \, dx &=-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {\int \frac {-2 a (c-d)-a (c-d) \sin (e+f x)}{(c+d \sin (e+f x))^2} \, dx}{2 \left (c^2-d^2\right )}\\ &=-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {a (c-2 d) \cos (e+f x)}{2 (c-d) (c+d)^2 f (c+d \sin (e+f x))}+\frac {\int \frac {a (c-d) (2 c-d)}{c+d \sin (e+f x)} \, dx}{2 \left (c^2-d^2\right )^2}\\ &=-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {a (c-2 d) \cos (e+f x)}{2 (c-d) (c+d)^2 f (c+d \sin (e+f x))}+\frac {(a (2 c-d)) \int \frac {1}{c+d \sin (e+f x)} \, dx}{2 (c-d) (c+d)^2}\\ &=-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {a (c-2 d) \cos (e+f x)}{2 (c-d) (c+d)^2 f (c+d \sin (e+f x))}+\frac {(a (2 c-d)) \text {Subst}\left (\int \frac {1}{c+2 d x+c x^2} \, dx,x,\tan \left (\frac {1}{2} (e+f x)\right )\right )}{(c-d) (c+d)^2 f}\\ &=-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {a (c-2 d) \cos (e+f x)}{2 (c-d) (c+d)^2 f (c+d \sin (e+f x))}-\frac {(2 a (2 c-d)) \text {Subst}\left (\int \frac {1}{-4 \left (c^2-d^2\right )-x^2} \, dx,x,2 d+2 c \tan \left (\frac {1}{2} (e+f x)\right )\right )}{(c-d) (c+d)^2 f}\\ &=\frac {a (2 c-d) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{(c-d) (c+d)^2 \sqrt {c^2-d^2} f}-\frac {a \cos (e+f x)}{2 (c+d) f (c+d \sin (e+f x))^2}-\frac {a (c-2 d) \cos (e+f x)}{2 (c-d) (c+d)^2 f (c+d \sin (e+f x))}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 0.79, size = 242, normalized size = 1.81 \begin {gather*} \frac {a (1+\sin (e+f x)) \left (\frac {4 (2 c-d) \tan ^{-1}\left (\frac {\sec \left (\frac {f x}{2}\right ) (\cos (e)-i \sin (e)) \left (d \cos \left (e+\frac {f x}{2}\right )+c \sin \left (\frac {f x}{2}\right )\right )}{\sqrt {c^2-d^2} \sqrt {(\cos (e)-i \sin (e))^2}}\right ) (\cos (e)-i \sin (e))}{(c-d) \sqrt {c^2-d^2} \sqrt {(\cos (e)-i \sin (e))^2}}+\frac {2 (c+d) \csc (e) (c \cos (e)+d \sin (f x))}{d (c+d \sin (e+f x))^2}+\frac {(-4 c+2 d) \cot (e)+2 (c-2 d) \csc (e) \sin (f x)}{(c-d) (c+d \sin (e+f x))}\right )}{4 (c+d)^2 f \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(324\) vs.
\(2(125)=250\).
time = 0.54, size = 325, normalized size = 2.43
method | result | size |
derivativedivides | \(\frac {2 a \left (\frac {-\frac {d \left (3 c^{2}-2 c d -2 d^{2}\right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right ) c}-\frac {\left (2 c^{4}-2 c^{3} d +3 c^{2} d^{2}-4 d^{3} c -2 d^{4}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right ) c^{2}}-\frac {d \left (5 c^{2}-6 c d -2 d^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{2 c \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right )}-\frac {2 c^{2}-2 c d -d^{2}}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right )}}{\left (c \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+2 d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+c \right )^{2}}+\frac {\left (2 c -d \right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right ) \sqrt {c^{2}-d^{2}}}\right )}{f}\) | \(325\) |
default | \(\frac {2 a \left (\frac {-\frac {d \left (3 c^{2}-2 c d -2 d^{2}\right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right ) c}-\frac {\left (2 c^{4}-2 c^{3} d +3 c^{2} d^{2}-4 d^{3} c -2 d^{4}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right ) c^{2}}-\frac {d \left (5 c^{2}-6 c d -2 d^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{2 c \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right )}-\frac {2 c^{2}-2 c d -d^{2}}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right )}}{\left (c \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+2 d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+c \right )^{2}}+\frac {\left (2 c -d \right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{2 \left (c^{3}+c^{2} d -c \,d^{2}-d^{3}\right ) \sqrt {c^{2}-d^{2}}}\right )}{f}\) | \(325\) |
risch | \(\frac {i a \left (2 i c \,d^{2} {\mathrm e}^{3 i \left (f x +e \right )}-i d^{3} {\mathrm e}^{3 i \left (f x +e \right )}+4 i c^{2} d \,{\mathrm e}^{i \left (f x +e \right )}-6 i c \,d^{2} {\mathrm e}^{i \left (f x +e \right )}-i d^{3} {\mathrm e}^{i \left (f x +e \right )}+2 c^{3} {\mathrm e}^{2 i \left (f x +e \right )}-4 d \,c^{2} {\mathrm e}^{2 i \left (f x +e \right )}+d^{2} {\mathrm e}^{2 i \left (f x +e \right )} c -2 d^{3} {\mathrm e}^{2 i \left (f x +e \right )}-c \,d^{2}+2 d^{3}\right )}{\left (-i d \,{\mathrm e}^{2 i \left (f x +e \right )}+i d +2 c \,{\mathrm e}^{i \left (f x +e \right )}\right )^{2} \left (c +d \right )^{2} \left (c -d \right ) f d}-\frac {a \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c \sqrt {-c^{2}+d^{2}}-c^{2}+d^{2}}{\sqrt {-c^{2}+d^{2}}\, d}\right ) c}{\sqrt {-c^{2}+d^{2}}\, \left (c +d \right )^{2} \left (c -d \right ) f}+\frac {a \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c \sqrt {-c^{2}+d^{2}}-c^{2}+d^{2}}{\sqrt {-c^{2}+d^{2}}\, d}\right ) d}{2 \sqrt {-c^{2}+d^{2}}\, \left (c +d \right )^{2} \left (c -d \right ) f}+\frac {a \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c \sqrt {-c^{2}+d^{2}}+c^{2}-d^{2}}{\sqrt {-c^{2}+d^{2}}\, d}\right ) c}{\sqrt {-c^{2}+d^{2}}\, \left (c +d \right )^{2} \left (c -d \right ) f}-\frac {a \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c \sqrt {-c^{2}+d^{2}}+c^{2}-d^{2}}{\sqrt {-c^{2}+d^{2}}\, d}\right ) d}{2 \sqrt {-c^{2}+d^{2}}\, \left (c +d \right )^{2} \left (c -d \right ) f}\) | \(522\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 368 vs.
\(2 (130) = 260\).
time = 0.38, size = 826, normalized size = 6.16 \begin {gather*} \left [\frac {2 \, {\left (a c^{3} d - 2 \, a c^{2} d^{2} - a c d^{3} + 2 \, a d^{4}\right )} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left (2 \, a c^{3} - a c^{2} d + 2 \, a c d^{2} - a d^{3} - {\left (2 \, a c d^{2} - a d^{3}\right )} \cos \left (f x + e\right )^{2} + 2 \, {\left (2 \, a c^{2} d - a c d^{2}\right )} \sin \left (f x + e\right )\right )} \sqrt {-c^{2} + d^{2}} \log \left (\frac {{\left (2 \, c^{2} - d^{2}\right )} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2} + 2 \, {\left (c \cos \left (f x + e\right ) \sin \left (f x + e\right ) + d \cos \left (f x + e\right )\right )} \sqrt {-c^{2} + d^{2}}}{d^{2} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2}}\right ) + 2 \, {\left (2 \, a c^{4} - 2 \, a c^{3} d - 3 \, a c^{2} d^{2} + 2 \, a c d^{3} + a d^{4}\right )} \cos \left (f x + e\right )}{4 \, {\left ({\left (c^{5} d^{2} + c^{4} d^{3} - 2 \, c^{3} d^{4} - 2 \, c^{2} d^{5} + c d^{6} + d^{7}\right )} f \cos \left (f x + e\right )^{2} - 2 \, {\left (c^{6} d + c^{5} d^{2} - 2 \, c^{4} d^{3} - 2 \, c^{3} d^{4} + c^{2} d^{5} + c d^{6}\right )} f \sin \left (f x + e\right ) - {\left (c^{7} + c^{6} d - c^{5} d^{2} - c^{4} d^{3} - c^{3} d^{4} - c^{2} d^{5} + c d^{6} + d^{7}\right )} f\right )}}, \frac {{\left (a c^{3} d - 2 \, a c^{2} d^{2} - a c d^{3} + 2 \, a d^{4}\right )} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left (2 \, a c^{3} - a c^{2} d + 2 \, a c d^{2} - a d^{3} - {\left (2 \, a c d^{2} - a d^{3}\right )} \cos \left (f x + e\right )^{2} + 2 \, {\left (2 \, a c^{2} d - a c d^{2}\right )} \sin \left (f x + e\right )\right )} \sqrt {c^{2} - d^{2}} \arctan \left (-\frac {c \sin \left (f x + e\right ) + d}{\sqrt {c^{2} - d^{2}} \cos \left (f x + e\right )}\right ) + {\left (2 \, a c^{4} - 2 \, a c^{3} d - 3 \, a c^{2} d^{2} + 2 \, a c d^{3} + a d^{4}\right )} \cos \left (f x + e\right )}{2 \, {\left ({\left (c^{5} d^{2} + c^{4} d^{3} - 2 \, c^{3} d^{4} - 2 \, c^{2} d^{5} + c d^{6} + d^{7}\right )} f \cos \left (f x + e\right )^{2} - 2 \, {\left (c^{6} d + c^{5} d^{2} - 2 \, c^{4} d^{3} - 2 \, c^{3} d^{4} + c^{2} d^{5} + c d^{6}\right )} f \sin \left (f x + e\right ) - {\left (c^{7} + c^{6} d - c^{5} d^{2} - c^{4} d^{3} - c^{3} d^{4} - c^{2} d^{5} + c d^{6} + d^{7}\right )} f\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 384 vs.
\(2 (130) = 260\).
time = 0.53, size = 384, normalized size = 2.87 \begin {gather*} \frac {\frac {{\left (\pi \left \lfloor \frac {f x + e}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (c\right ) + \arctan \left (\frac {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + d}{\sqrt {c^{2} - d^{2}}}\right )\right )} {\left (2 \, a c - a d\right )}}{{\left (c^{3} + c^{2} d - c d^{2} - d^{3}\right )} \sqrt {c^{2} - d^{2}}} - \frac {3 \, a c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 2 \, a c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 2 \, a c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, a c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 2 \, a c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 3 \, a c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 4 \, a c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 2 \, a d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 5 \, a c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 6 \, a c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 2 \, a c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 2 \, a c^{4} - 2 \, a c^{3} d - a c^{2} d^{2}}{{\left (c^{5} + c^{4} d - c^{3} d^{2} - c^{2} d^{3}\right )} {\left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + c\right )}^{2}}}{f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 8.97, size = 445, normalized size = 3.32 \begin {gather*} -\frac {\frac {-2\,a\,c^2+2\,a\,c\,d+a\,d^2}{-c^3-c^2\,d+c\,d^2+d^3}+\frac {a\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (c^2+2\,d^2\right )\,\left (-2\,c^2+2\,c\,d+d^2\right )}{c^2\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}+\frac {a\,d\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (-5\,c^2+6\,c\,d+2\,d^2\right )}{c\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}+\frac {a\,d\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (-3\,c^2+2\,c\,d+2\,d^2\right )}{c\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}}{f\,\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (2\,c^2+4\,d^2\right )+c^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4+c^2+4\,c\,d\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3+4\,c\,d\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )}-\frac {a\,\mathrm {atan}\left (\frac {\left (\frac {a\,\left (2\,c-d\right )\,\left (-2\,c^3\,d-2\,c^2\,d^2+2\,c\,d^3+2\,d^4\right )}{2\,{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{3/2}\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}+\frac {a\,c\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (2\,c-d\right )}{{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{3/2}}\right )\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}{2\,a\,c-a\,d}\right )\,\left (2\,c-d\right )}{f\,{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{3/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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